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(2x)(3.2x)=(1.2x)(4x)
We move all terms to the left:
(2x)(3.2x)-((1.2x)(4x))=0
We add all the numbers together, and all the variables
2x(+3.2x)-((+1.2x)4x)=0
We multiply parentheses
6x^2-((+1.2x)4x)=0
We calculate terms in parentheses: -((+1.2x)4x), so:We add all the numbers together, and all the variables
(+1.2x)4x
We multiply parentheses
4x^2
Back to the equation:
-(4x^2)
2x^2=0
a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{4}=0$
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