(2x)(x=31)

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Solution for (2x)(x=31) equation:



(2x)(x=31)
We move all terms to the left:
(2x)(x-(31))=0
We multiply parentheses
2x^2-62x=0
a = 2; b = -62; c = 0;
Δ = b2-4ac
Δ = -622-4·2·0
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-62}{2*2}=\frac{0}{4} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+62}{2*2}=\frac{124}{4} =31 $

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