(2x)(x+14)(x-38)x=

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Solution for (2x)(x+14)(x-38)x= equation:


Simplifying
(2x)(x + 14)(x + -38) * x = 0

Remove parenthesis around (2x)
2x(x + 14)(x + -38) * x = 0

Reorder the terms:
2x(14 + x)(x + -38) * x = 0

Reorder the terms:
2x(14 + x)(-38 + x) * x = 0

Reorder the terms for easier multiplication:
2x * x(14 + x)(-38 + x) = 0

Multiply x * x
2x2(14 + x)(-38 + x) = 0

Multiply (14 + x) * (-38 + x)
2x2(14(-38 + x) + x(-38 + x)) = 0
2x2((-38 * 14 + x * 14) + x(-38 + x)) = 0
2x2((-532 + 14x) + x(-38 + x)) = 0
2x2(-532 + 14x + (-38 * x + x * x)) = 0
2x2(-532 + 14x + (-38x + x2)) = 0

Combine like terms: 14x + -38x = -24x
2x2(-532 + -24x + x2) = 0
(-532 * 2x2 + -24x * 2x2 + x2 * 2x2) = 0
(-1064x2 + -48x3 + 2x4) = 0

Solving
-1064x2 + -48x3 + 2x4 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2x2'.
2x2(-532 + -24x + x2) = 0

Factor a trinomial.
2x2((-14 + -1x)(38 + -1x)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor 'x2' equal to zero and attempt to solve: Simplifying x2 = 0 Solving x2 = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x2 = 0 Take the square root of each side: x = {0}

Subproblem 2

Set the factor '(-14 + -1x)' equal to zero and attempt to solve: Simplifying -14 + -1x = 0 Solving -14 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '14' to each side of the equation. -14 + 14 + -1x = 0 + 14 Combine like terms: -14 + 14 = 0 0 + -1x = 0 + 14 -1x = 0 + 14 Combine like terms: 0 + 14 = 14 -1x = 14 Divide each side by '-1'. x = -14 Simplifying x = -14

Subproblem 3

Set the factor '(38 + -1x)' equal to zero and attempt to solve: Simplifying 38 + -1x = 0 Solving 38 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-38' to each side of the equation. 38 + -38 + -1x = 0 + -38 Combine like terms: 38 + -38 = 0 0 + -1x = 0 + -38 -1x = 0 + -38 Combine like terms: 0 + -38 = -38 -1x = -38 Divide each side by '-1'. x = 38 Simplifying x = 38

Solution

x = {0, -14, 38}

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