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(2x)(x)(x+4)=450
We move all terms to the left:
(2x)(x)(x+4)-(450)=0
We multiply parentheses
2x^2+8x-450=0
a = 2; b = 8; c = -450;
Δ = b2-4ac
Δ = 82-4·2·(-450)
Δ = 3664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3664}=\sqrt{16*229}=\sqrt{16}*\sqrt{229}=4\sqrt{229}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{229}}{2*2}=\frac{-8-4\sqrt{229}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{229}}{2*2}=\frac{-8+4\sqrt{229}}{4} $
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