(2w-7)(1-w)=0

Solution for (2w-7)(1-w)=0 equation:

(2w-7)(1-w)=0

We add all the numbers together, and all the variables

(2w-7)(-1w+1)=0

We multiply parentheses ..

(-2w^2+2w+7w-7)=0

We get rid of parentheses

-2w^2+2w+7w-7=0

We add all the numbers together, and all the variables

-2w^2+9w-7=0

a = -2; b = 9; c = -7;
Δ = b2-4ac
Δ = 92-4·(-2)·(-7)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-5}{2*-2}=\frac{-14}{-4}
=3+1/2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+5}{2*-2}=\frac{-4}{-4}
=1
$