(2w+i)/w-i=(3w+4i)/w+3i

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Solution for (2w+i)/w-i=(3w+4i)/w+3i equation: 


x in (-oo:+oo)

(i+2*w)/w-i = (4*i+3*w)/w+3*i // - (4*i+3*w)/w+3*i

(i+2*w)/w-((4*i+3*w)/w)-i-(3*i) = 0

(i+2*w)/w-((4*i+3*w)/w)-i-3*i = 0

(i+2*w)/w+(-1*(4*i+3*w))/w-i-3*i = 0

(i+2*w)/w+(-1*(4*i+3*w))/w+(-i*w)/w+(-3*i*w)/w = 0

i-1*(4*i+3*w)+2*w-i*w-3*i*w = 0

-3*i-w-(i*w)-3*i*w = 0

-3*i-w-4*i*w = 0

(-3*i-w-4*i*w)/w = 0

(-3*i-w-4*i*w)/w = 0 // * w

-3*i-w-4*i*w = 0

x belongs to the empty set

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