(2v-5)(6-v)=0

Solution for (2v-5)(6-v)=0 equation:

(2v-5)(6-v)=0

We add all the numbers together, and all the variables

(2v-5)(-1v+6)=0

We multiply parentheses ..

(-2v^2+12v+5v-30)=0

We get rid of parentheses

-2v^2+12v+5v-30=0

We add all the numbers together, and all the variables

-2v^2+17v-30=0

a = -2; b = 17; c = -30;
Δ = b2-4ac
Δ = 172-4·(-2)·(-30)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-7}{2*-2}=\frac{-24}{-4}
=+6
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+7}{2*-2}=\frac{-10}{-4}
=2+1/2
$