(2v-1)(7+v)=0

Solution for (2v-1)(7+v)=0 equation:

(2v-1)(7+v)=0

We add all the numbers together, and all the variables

(2v-1)(v+7)=0

We multiply parentheses ..

(+2v^2+14v-1v-7)=0

We get rid of parentheses

2v^2+14v-1v-7=0

We add all the numbers together, and all the variables

2v^2+13v-7=0

a = 2; b = 13; c = -7;
Δ = b2-4ac
Δ = 132-4·2·(-7)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-15}{2*2}=\frac{-28}{4}
=-7
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+15}{2*2}=\frac{2}{4}
=1/2
$