(2v+9)(v+7)=0

Solution for (2v+9)(v+7)=0 equation:

(2v+9)(v+7)=0

We multiply parentheses ..

(+2v^2+14v+9v+63)=0

We get rid of parentheses

2v^2+14v+9v+63=0

We add all the numbers together, and all the variables

2v^2+23v+63=0

a = 2; b = 23; c = +63;
Δ = b2-4ac
Δ = 232-4·2·63
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-5}{2*2}=\frac{-28}{4}
=-7
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+5}{2*2}=\frac{-18}{4}
=-4+1/2
$