(2u+5)(1-u)=0

Solution for (2u+5)(1-u)=0 equation:

Simplifying
(2u + 5)(1 + -1u) = 0

Reorder the terms:
(5 + 2u)(1 + -1u) = 0

Multiply (5 + 2u) * (1 + -1u)
(5(1 + -1u) + 2u * (1 + -1u)) = 0
((1 * 5 + -1u * 5) + 2u * (1 + -1u)) = 0
((5 + -5u) + 2u * (1 + -1u)) = 0
(5 + -5u + (1 * 2u + -1u * 2u)) = 0
(5 + -5u + (2u + -2u2)) = 0

Combine like terms: -5u + 2u = -3u
(5 + -3u + -2u2) = 0

Solving
5 + -3u + -2u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(1 + -1u)(5 + 2u) = 0

Subproblem 1
Set the factor '(1 + -1u)' equal to zero and attempt to solve:

Simplifying
1 + -1u = 0

Solving
1 + -1u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1u = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1u = 0 + -1
-1u = 0 + -1

Combine like terms: 0 + -1 = -1
-1u = -1

Divide each side by '-1'.
u = 1

Simplifying
u = 1
Subproblem 2
Set the factor '(5 + 2u)' equal to zero and attempt to solve:

Simplifying
5 + 2u = 0

Solving
5 + 2u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + 2u = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 2u = 0 + -5
2u = 0 + -5

Combine like terms: 0 + -5 = -5
2u = -5

Divide each side by '2'.
u = -2.5

Simplifying
u = -2.5
Solution
u = {1, -2.5}