(2u+1)(7+u)=0

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Solution for (2u+1)(7+u)=0 equation:


Simplifying
(2u + 1)(7 + u) = 0

Reorder the terms:
(1 + 2u)(7 + u) = 0

Multiply (1 + 2u) * (7 + u)
(1(7 + u) + 2u * (7 + u)) = 0
((7 * 1 + u * 1) + 2u * (7 + u)) = 0
((7 + 1u) + 2u * (7 + u)) = 0
(7 + 1u + (7 * 2u + u * 2u)) = 0
(7 + 1u + (14u + 2u2)) = 0

Combine like terms: 1u + 14u = 15u
(7 + 15u + 2u2) = 0

Solving
7 + 15u + 2u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(7 + u)(1 + 2u) = 0

Subproblem 1

Set the factor '(7 + u)' equal to zero and attempt to solve: Simplifying 7 + u = 0 Solving 7 + u = 0 Move all terms containing u to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + u = 0 + -7 Combine like terms: 7 + -7 = 0 0 + u = 0 + -7 u = 0 + -7 Combine like terms: 0 + -7 = -7 u = -7 Simplifying u = -7

Subproblem 2

Set the factor '(1 + 2u)' equal to zero and attempt to solve: Simplifying 1 + 2u = 0 Solving 1 + 2u = 0 Move all terms containing u to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 2u = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 2u = 0 + -1 2u = 0 + -1 Combine like terms: 0 + -1 = -1 2u = -1 Divide each side by '2'. u = -0.5 Simplifying u = -0.5

Solution

u = {-7, -0.5}

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