(2t-7)+(-t+2)=0

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Solution for (2t-7)+(-t+2)=0 equation:


Simplifying
(2t + -7) + (-1t + 2) = 0

Reorder the terms:
(-7 + 2t) + (-1t + 2) = 0

Remove parenthesis around (-7 + 2t)
-7 + 2t + (-1t + 2) = 0

Reorder the terms:
-7 + 2t + (2 + -1t) = 0

Remove parenthesis around (2 + -1t)
-7 + 2t + 2 + -1t = 0

Reorder the terms:
-7 + 2 + 2t + -1t = 0

Combine like terms: -7 + 2 = -5
-5 + 2t + -1t = 0

Combine like terms: 2t + -1t = 1t
-5 + 1t = 0

Solving
-5 + 1t = 0

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 1t = 0 + 5

Combine like terms: -5 + 5 = 0
0 + 1t = 0 + 5
1t = 0 + 5

Combine like terms: 0 + 5 = 5
1t = 5

Divide each side by '1'.
t = 5

Simplifying
t = 5

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