(2t-4)(2t+4)=

Solution for (2t-4)(2t+4)= equation:

Simplifying
(2t + -4)(2t + 4) = 0

Reorder the terms:
(-4 + 2t)(2t + 4) = 0

Reorder the terms:
(-4 + 2t)(4 + 2t) = 0

Multiply (-4 + 2t) * (4 + 2t)
(-4(4 + 2t) + 2t * (4 + 2t)) = 0
((4 * -4 + 2t * -4) + 2t * (4 + 2t)) = 0
((-16 + -8t) + 2t * (4 + 2t)) = 0
(-16 + -8t + (4 * 2t + 2t * 2t)) = 0
(-16 + -8t + (8t + 4t2)) = 0

Combine like terms: -8t + 8t = 0
(-16 + 0 + 4t2) = 0
(-16 + 4t2) = 0

Solving
-16 + 4t2 = 0

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 4t2 = 0 + 16

Combine like terms: -16 + 16 = 0
0 + 4t2 = 0 + 16
4t2 = 0 + 16

Combine like terms: 0 + 16 = 16
4t2 = 16

Divide each side by '4'.
t2 = 4

Simplifying
t2 = 4

Take the square root of each side:
t = {-2, 2}