(2t+4)(2t+4)=

Solution for (2t+4)(2t+4)= equation:

Simplifying
(2t + 4)(2t + 4) = 0

Reorder the terms:
(4 + 2t)(2t + 4) = 0

Reorder the terms:
(4 + 2t)(4 + 2t) = 0

Multiply (4 + 2t) * (4 + 2t)
(4(4 + 2t) + 2t * (4 + 2t)) = 0
((4 * 4 + 2t * 4) + 2t * (4 + 2t)) = 0
((16 + 8t) + 2t * (4 + 2t)) = 0
(16 + 8t + (4 * 2t + 2t * 2t)) = 0
(16 + 8t + (8t + 4t2)) = 0

Combine like terms: 8t + 8t = 16t
(16 + 16t + 4t2) = 0

Solving
16 + 16t + 4t2 = 0

Solving for variable 't'.

Factor out the Greatest Common Factor (GCF), '4'.
4(4 + 4t + t2) = 0

Factor a trinomial.
4((2 + t)(2 + t)) = 0

Ignore the factor 4.
Subproblem 1
Set the factor '(2 + t)' equal to zero and attempt to solve:

Simplifying
2 + t = 0

Solving
2 + t = 0

Move all terms containing t to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + t = 0 + -2

Combine like terms: 2 + -2 = 0
0 + t = 0 + -2
t = 0 + -2

Combine like terms: 0 + -2 = -2
t = -2

Simplifying
t = -2
Subproblem 2
Set the factor '(2 + t)' equal to zero and attempt to solve:

Simplifying
2 + t = 0

Solving
2 + t = 0

Move all terms containing t to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + t = 0 + -2

Combine like terms: 2 + -2 = 0
0 + t = 0 + -2
t = 0 + -2

Combine like terms: 0 + -2 = -2
t = -2

Simplifying
t = -2
Solution
t = {-2, -2}