(2t+3)2-(2t-3)/4t

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Solution for (2t+3)2-(2t-3)/4t equation:


t in (-oo:+oo)

(2*t+3)^2-(t*((2*t-3)/4)) = 0

(2*t+3)^2+(-1*t*(2*t-3))/4 = 0

(4*(2*t+3)^2)/4+(-1*t*(2*t-3))/4 = 0

4*(2*t+3)^2-1*t*(2*t-3) = 0

14*t^2+51*t+36 = 0

14*t^2+51*t+36 = 0

14*t^2+51*t+36 = 0

DELTA = 51^2-(4*14*36)

DELTA = 585

DELTA > 0

t = (585^(1/2)-51)/(2*14) or t = (-585^(1/2)-51)/(2*14)

t = (3*65^(1/2)-51)/28 or t = (-3*65^(1/2)-51)/28

(t-((-3*65^(1/2)-51)/28))*(t-((3*65^(1/2)-51)/28)) = 0

((t-((-3*65^(1/2)-51)/28))*(t-((3*65^(1/2)-51)/28)))/4 = 0

((t-((-3*65^(1/2)-51)/28))*(t-((3*65^(1/2)-51)/28)))/4 = 0 // * 4

(t-((-3*65^(1/2)-51)/28))*(t-((3*65^(1/2)-51)/28)) = 0

( t-((-3*65^(1/2)-51)/28) )

t-((-3*65^(1/2)-51)/28) = 0 // + (-3*65^(1/2)-51)/28

t = (-3*65^(1/2)-51)/28

( t-((3*65^(1/2)-51)/28) )

t-((3*65^(1/2)-51)/28) = 0 // + (3*65^(1/2)-51)/28

t = (3*65^(1/2)-51)/28

t in { (-3*65^(1/2)-51)/28, (3*65^(1/2)-51)/28 }

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