(2t+1)-3(2t-5)=29

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Solution for (2t+1)-3(2t-5)=29 equation:


Simplifying
(2t + 1) + -3(2t + -5) = 29

Reorder the terms:
(1 + 2t) + -3(2t + -5) = 29

Remove parenthesis around (1 + 2t)
1 + 2t + -3(2t + -5) = 29

Reorder the terms:
1 + 2t + -3(-5 + 2t) = 29
1 + 2t + (-5 * -3 + 2t * -3) = 29
1 + 2t + (15 + -6t) = 29

Reorder the terms:
1 + 15 + 2t + -6t = 29

Combine like terms: 1 + 15 = 16
16 + 2t + -6t = 29

Combine like terms: 2t + -6t = -4t
16 + -4t = 29

Solving
16 + -4t = 29

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + -4t = 29 + -16

Combine like terms: 16 + -16 = 0
0 + -4t = 29 + -16
-4t = 29 + -16

Combine like terms: 29 + -16 = 13
-4t = 13

Divide each side by '-4'.
t = -3.25

Simplifying
t = -3.25

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