(2r+6)/8=(2r-12)/2

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Solution for (2r+6)/8=(2r-12)/2 equation: 



(2r+6)/8=(2r-12)/2

We move all terms to the left:

(2r+6)/8-((2r-12)/2)=0

We calculate fractions


2r/()+(-((2r-12)*8)/()=0



We calculate terms in parentheses: +(-((2r-12)*8)/(), so:

-((2r-12)*8)/(

We multiply all the terms by the denominator


-((2r-12)*8)



We calculate terms in parentheses: -((2r-12)*8), so:

(2r-12)*8

We multiply parentheses

16r-96

Back to the equation:

-(16r-96)



We get rid of parentheses

-16r+96

Back to the equation:

+(-16r+96)



We get rid of parentheses

2r/()-16r+96=0

We multiply all the terms by the denominator


2r-16r*()+96*()=0

We add all the numbers together, and all the variables

2r-16r*()=0

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