(2r+4)+(r+5)=190

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Solution for (2r+4)+(r+5)=190 equation: 



(2r+4)+(r+5)=190

We move all terms to the left:

(2r+4)+(r+5)-(190)=0

We get rid of parentheses

2r+r+4+5-190=0

We add all the numbers together, and all the variables

3r-181=0

We move all terms containing r to the left, all other terms to the right

3r=181

r=181/3

r=60+1/3

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