(2q-1)/4=(3q+5)/8)

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Solution for (2q-1)/4=(3q+5)/8) equation: 



(2q-1)/4=(3q+5)/8)

We move all terms to the left:

(2q-1)/4-((3q+5)/8))=0

We calculate fractions


2q/()+(-((3q+5)*4)/()=0



We calculate terms in parentheses: +(-((3q+5)*4)/(), so:

-((3q+5)*4)/(

We multiply all the terms by the denominator


-((3q+5)*4)



We calculate terms in parentheses: -((3q+5)*4), so:

(3q+5)*4

We multiply parentheses

12q+20

Back to the equation:

-(12q+20)



We get rid of parentheses

-12q-20

Back to the equation:

+(-12q-20)



We get rid of parentheses

2q/()-12q-20=0

We multiply all the terms by the denominator


2q-12q*()-20*()=0

We add all the numbers together, and all the variables

2q-12q*()=0

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