(2p-5q)(5q+2p)=

Solution for (2p-5q)(5q+2p)= equation:

Simplifying
(2p + -5q)(5q + 2p) = 0

Reorder the terms:
(2p + -5q)(2p + 5q) = 0

Multiply (2p + -5q) * (2p + 5q)
(2p * (2p + 5q) + -5q * (2p + 5q)) = 0
((2p * 2p + 5q * 2p) + -5q * (2p + 5q)) = 0

Reorder the terms:
((10pq + 4p2) + -5q * (2p + 5q)) = 0
((10pq + 4p2) + -5q * (2p + 5q)) = 0
(10pq + 4p2 + (2p * -5q + 5q * -5q)) = 0
(10pq + 4p2 + (-10pq + -25q2)) = 0

Reorder the terms:
(10pq + -10pq + 4p2 + -25q2) = 0

Combine like terms: 10pq + -10pq = 0
(0 + 4p2 + -25q2) = 0
(4p2 + -25q2) = 0

Solving
4p2 + -25q2 = 0

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '25q2' to each side of the equation.
4p2 + -25q2 + 25q2 = 0 + 25q2

Combine like terms: -25q2 + 25q2 = 0
4p2 + 0 = 0 + 25q2
4p2 = 0 + 25q2
Remove the zero:
4p2 = 25q2

Divide each side by '4'.
p2 = 6.25q2

Simplifying
p2 = 6.25q2

Take the square root of each side:
p = {-2.5q, 2.5q}