(2p-4)-(q+1)=0

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Solution for (2p-4)-(q+1)=0 equation:


Simplifying
(2p + -4) + -1(q + 1) = 0

Reorder the terms:
(-4 + 2p) + -1(q + 1) = 0

Remove parenthesis around (-4 + 2p)
-4 + 2p + -1(q + 1) = 0

Reorder the terms:
-4 + 2p + -1(1 + q) = 0
-4 + 2p + (1 * -1 + q * -1) = 0
-4 + 2p + (-1 + -1q) = 0

Reorder the terms:
-4 + -1 + 2p + -1q = 0

Combine like terms: -4 + -1 = -5
-5 + 2p + -1q = 0

Solving
-5 + 2p + -1q = 0

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 2p + 5 + -1q = 0 + 5

Reorder the terms:
-5 + 5 + 2p + -1q = 0 + 5

Combine like terms: -5 + 5 = 0
0 + 2p + -1q = 0 + 5
2p + -1q = 0 + 5

Combine like terms: 0 + 5 = 5
2p + -1q = 5

Add 'q' to each side of the equation.
2p + -1q + q = 5 + q

Combine like terms: -1q + q = 0
2p + 0 = 5 + q
2p = 5 + q

Divide each side by '2'.
p = 2.5 + 0.5q

Simplifying
p = 2.5 + 0.5q

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