(2p-35)+(4p-26)+(p-4)=180

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Solution for (2p-35)+(4p-26)+(p-4)=180 equation: 



(2p-35)+(4p-26)+(p-4)=180

We move all terms to the left:

(2p-35)+(4p-26)+(p-4)-(180)=0

We get rid of parentheses

2p+4p+p-35-26-4-180=0

We add all the numbers together, and all the variables

7p-245=0

We move all terms containing p to the left, all other terms to the right

7p=245

p=245/7

p=35

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