(2p+5)(p+5)=0

Solution for (2p+5)(p+5)=0 equation:

(2p+5)(p+5)=0

We multiply parentheses ..

(+2p^2+10p+5p+25)=0

We get rid of parentheses

2p^2+10p+5p+25=0

We add all the numbers together, and all the variables

2p^2+15p+25=0

a = 2; b = 15; c = +25;
Δ = b2-4ac
Δ = 152-4·2·25
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-5}{2*2}=\frac{-20}{4}
=-5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+5}{2*2}=\frac{-10}{4}
=-2+1/2
$