(2p+3)(p+3)=0

Solution for (2p+3)(p+3)=0 equation:

(2p+3)(p+3)=0

We multiply parentheses ..

(+2p^2+6p+3p+9)=0

We get rid of parentheses

2p^2+6p+3p+9=0

We add all the numbers together, and all the variables

2p^2+9p+9=0

a = 2; b = 9; c = +9;
Δ = b2-4ac
Δ = 92-4·2·9
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-3}{2*2}=\frac{-12}{4}
=-3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+3}{2*2}=\frac{-6}{4}
=-1+1/2
$