(2n-4)+(n+3)-n=23

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Solution for (2n-4)+(n+3)-n=23 equation: 



(2n-4)+(n+3)-n=23

We move all terms to the left:

(2n-4)+(n+3)-n-(23)=0

We add all the numbers together, and all the variables

-1n+(2n-4)+(n+3)-23=0

We get rid of parentheses

-1n+2n+n-4+3-23=0

We add all the numbers together, and all the variables

2n-24=0

We move all terms containing n to the left, all other terms to the right

2n=24

n=24/2

n=12

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