(2n-3)-2(6n+1)=10

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Solution for (2n-3)-2(6n+1)=10 equation: 



(2n-3)-2(6n+1)=10

We move all terms to the left:

(2n-3)-2(6n+1)-(10)=0

We multiply parentheses

(2n-3)-12n-2-10=0

We get rid of parentheses

2n-12n-3-2-10=0

We add all the numbers together, and all the variables

-10n-15=0

We move all terms containing n to the left, all other terms to the right

-10n=15

n=15/-10

n=-1+1/2

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