(2n-18)=(n+53)

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Solution for (2n-18)=(n+53) equation: 



(2n-18)=(n+53)

We move all terms to the left:

(2n-18)-((n+53))=0

We get rid of parentheses

2n-((n+53))-18=0



We calculate terms in parentheses: -((n+53)), so:

(n+53)

We get rid of parentheses

n+53

Back to the equation:

-(n+53)



We get rid of parentheses

2n-n-53-18=0

We add all the numbers together, and all the variables

n-71=0

We move all terms containing n to the left, all other terms to the right

n=71

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