(2n-1)(2n-1)=0

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Solution for (2n-1)(2n-1)=0 equation: 



(2n-1)(2n-1)=0

We multiply parentheses ..

(+4n^2-2n-2n+1)=0

We get rid of parentheses

4n^2-2n-2n+1=0

We add all the numbers together, and all the variables

4n^2-4n+1=0

a = 4; b = -4; c = +1;
Δ = b2-4ac
Δ = -42-4·4·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{4}{8}=1/2$

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