(2n+8)-(n+4)=16-n

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Solution for (2n+8)-(n+4)=16-n equation: 



(2n+8)-(n+4)=16-n

We move all terms to the left:

(2n+8)-(n+4)-(16-n)=0

We add all the numbers together, and all the variables

(2n+8)-(n+4)-(-1n+16)=0

We get rid of parentheses

2n-n+1n+8-4-16=0

We add all the numbers together, and all the variables

2n-12=0

We move all terms containing n to the left, all other terms to the right

2n=12

n=12/2

n=6

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