(2n+3)+n=33

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Solution for (2n+3)+n=33 equation: 



(2n+3)+n=33

We move all terms to the left:

(2n+3)+n-(33)=0

We add all the numbers together, and all the variables

n+(2n+3)-33=0

We get rid of parentheses

n+2n+3-33=0

We add all the numbers together, and all the variables

3n-30=0

We move all terms containing n to the left, all other terms to the right

3n=30

n=30/3

n=10

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