(2n+1)+(2n+3)+(2n+5)=141

Solution for (2n+1)+(2n+3)+(2n+5)=141 equation:

Simplifying
(2n + 1) + (2n + 3) + (2n + 5) = 141

Reorder the terms:
(1 + 2n) + (2n + 3) + (2n + 5) = 141

Remove parenthesis around (1 + 2n)
1 + 2n + (2n + 3) + (2n + 5) = 141

Reorder the terms:
1 + 2n + (3 + 2n) + (2n + 5) = 141

Remove parenthesis around (3 + 2n)
1 + 2n + 3 + 2n + (2n + 5) = 141

Reorder the terms:
1 + 2n + 3 + 2n + (5 + 2n) = 141

Remove parenthesis around (5 + 2n)
1 + 2n + 3 + 2n + 5 + 2n = 141

Reorder the terms:
1 + 3 + 5 + 2n + 2n + 2n = 141

Combine like terms: 1 + 3 = 4
4 + 5 + 2n + 2n + 2n = 141

Combine like terms: 4 + 5 = 9
9 + 2n + 2n + 2n = 141

Combine like terms: 2n + 2n = 4n
9 + 4n + 2n = 141

Combine like terms: 4n + 2n = 6n
9 + 6n = 141

Solving
9 + 6n = 141

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + 6n = 141 + -9

Combine like terms: 9 + -9 = 0
0 + 6n = 141 + -9
6n = 141 + -9

Combine like terms: 141 + -9 = 132
6n = 132

Divide each side by '6'.
n = 22

Simplifying
n = 22