(2n+1)+((2n+1)+2)+((2n+1)+4)=6n+9

Solution for (2n+1)+((2n+1)+2)+((2n+1)+4)=6n+9 equation:

(2n+1)+((2n+1)+2)+((2n+1)+4)=6n+9

We move all terms to the left:

(2n+1)+((2n+1)+2)+((2n+1)+4)-(6n+9)=0

We get rid of parentheses

2n+((2n+1)+2)+((2n+1)+4)-6n+1-9=0


We calculate terms in parentheses: +((2n+1)+2), so:

(2n+1)+2

We get rid of parentheses

2n+1+2

We add all the numbers together, and all the variables

2n+3

Back to the equation:

+(2n+3)



We calculate terms in parentheses: +((2n+1)+4), so:

(2n+1)+4

We get rid of parentheses

2n+1+4

We add all the numbers together, and all the variables

2n+5

Back to the equation:

+(2n+5)


We add all the numbers together, and all the variables

-4n+(2n+3)+(2n+5)-8=0

We get rid of parentheses

-4n+2n+2n+3+5-8=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0