(2n*0.10)+(n*0.25)+((n+2)*0.5)=2.60

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Solution for (2n*0.10)+(n*0.25)+((n+2)*0.5)=2.60 equation: 



(2n*0.10)+(n*0.25)+((n+2)*0.5)=2.60

We move all terms to the left:

(2n*0.10)+(n*0.25)+((n+2)*0.5)-(2.60)=0

We add all the numbers together, and all the variables

(+2n*0.10)+(+n*0.25)+((n+2)*0.5)-(2.6)=0

We add all the numbers together, and all the variables

(+2n*0.10)+(+n*0.25)+((n+2)*0.5)-2.6=0

We get rid of parentheses

2n*0.10+n*0.25+((n+2)*0.5)-2.6=0



We calculate terms in parentheses: +((n+2)*0.5), so:

(n+2)*0.5

We multiply parentheses

0.5n+1

Back to the equation:

+(0.5n+1)



Wy multiply elements

0.2n+0.25n+(0.5n+1)-2.6=0

We get rid of parentheses

0.2n+0.25n+0.5n+1-2.6=0

We add all the numbers together, and all the variables

0.95n-1.6=0

We move all terms containing n to the left, all other terms to the right

0.95n=1.6

n=1.6/0.95

n=1+0.65/0.95

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