(2m-7)(m-7)=0

Solution for (2m-7)(m-7)=0 equation:

(2m-7)(m-7)=0

We multiply parentheses ..

(+2m^2-14m-7m+49)=0

We get rid of parentheses

2m^2-14m-7m+49=0

We add all the numbers together, and all the variables

2m^2-21m+49=0

a = 2; b = -21; c = +49;
Δ = b2-4ac
Δ = -212-4·2·49
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-7}{2*2}=\frac{14}{4}
=3+1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+7}{2*2}=\frac{28}{4}
=7
$