(2m-5)(m-1)=2

Solution for (2m-5)(m-1)=2 equation:

(2m-5)(m-1)=2

We move all terms to the left:

(2m-5)(m-1)-(2)=0

We multiply parentheses ..

(+2m^2-2m-5m+5)-2=0

We get rid of parentheses

2m^2-2m-5m+5-2=0

We add all the numbers together, and all the variables

2m^2-7m+3=0

a = 2; b = -7; c = +3;
Δ = b2-4ac
Δ = -72-4·2·3
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-5}{2*2}=\frac{2}{4}
=1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+5}{2*2}=\frac{12}{4}
=3
$