(2m-5)(-2m)=-11

Solution for (2m-5)(-2m)=-11 equation:

(2m-5)(-2m)=-11

We move all terms to the left:

(2m-5)(-2m)-(-11)=0

We add all the numbers together, and all the variables

(2m-5)(-2m)+11=0

We multiply parentheses ..

(-4m^2+10m)+11=0

We get rid of parentheses

-4m^2+10m+11=0

a = -4; b = 10; c = +11;
Δ = b2-4ac
Δ = 102-4·(-4)·11
Δ = 276
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{276}=\sqrt{4*69}=\sqrt{4}*\sqrt{69}=2\sqrt{69}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{69}}{2*-4}=\frac{-10-2\sqrt{69}}{-8}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{69}}{2*-4}=\frac{-10+2\sqrt{69}}{-8}
$