(2m+3/m)=1

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Solution for (2m+3/m)=1 equation: 


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

2*m+3/m = 1 // - 1

2*m+3/m-1 = 0

2*m^1+3*m^-1-1*m^0 = 0

(2*m^2-1*m^1+3*m^0)/(m^1) = 0 // * m^2

m^1*(2*m^2-1*m^1+3*m^0) = 0

m^1

2*m^2-m+3 = 0

2*m^2-m+3 = 0

DELTA = (-1)^2-(2*3*4)

DELTA = -23

DELTA < 0

m in { } 

m belongs to the empty set

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