(2m+2)(m+3)=(m-3)

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Solution for (2m+2)(m+3)=(m-3) equation: 



(2m+2)(m+3)=(m-3)

We move all terms to the left:

(2m+2)(m+3)-((m-3))=0

We multiply parentheses ..

(+2m^2+6m+2m+6)-((m-3))=0



We calculate terms in parentheses: -((m-3)), so:

(m-3)

We get rid of parentheses

m-3

Back to the equation:

-(m-3)



We get rid of parentheses

2m^2+6m+2m-m+6+3=0

We add all the numbers together, and all the variables

2m^2+7m+9=0

a = 2; b = 7; c = +9;
Δ = b2-4ac
Δ = 72-4·2·9
Δ = -23
Delta is less than zero, so there is no solution for the equation

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