(2k+3)-(k-1)=(7-k)-(2k+3)

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Solution for (2k+3)-(k-1)=(7-k)-(2k+3) equation: 



(2k+3)-(k-1)=(7-k)-(2k+3)

We move all terms to the left:

(2k+3)-(k-1)-((7-k)-(2k+3))=0

We add all the numbers together, and all the variables

(2k+3)-(k-1)-((-1k+7)-(2k+3))=0

We get rid of parentheses

2k-k-((-1k+7)-(2k+3))+3+1=0



We calculate terms in parentheses: -((-1k+7)-(2k+3)), so:

(-1k+7)-(2k+3)

We get rid of parentheses

-1k-2k+7-3

We add all the numbers together, and all the variables

-3k+4

Back to the equation:

-(-3k+4)



We add all the numbers together, and all the variables

k-(-3k+4)+4=0

We get rid of parentheses

k+3k-4+4=0

We add all the numbers together, and all the variables

4k=0

k=0/4

k=0

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