(2j+4)(j+1)=

Solution for (2j+4)(j+1)= equation:

Simplifying
(2j + 4)(j + 1) = 0

Reorder the terms:
(4 + 2j)(j + 1) = 0

Reorder the terms:
(4 + 2j)(1 + j) = 0

Multiply (4 + 2j) * (1 + j)
(4(1 + j) + 2j * (1 + j)) = 0
((1 * 4 + j * 4) + 2j * (1 + j)) = 0
((4 + 4j) + 2j * (1 + j)) = 0
(4 + 4j + (1 * 2j + j * 2j)) = 0
(4 + 4j + (2j + 2j2)) = 0

Combine like terms: 4j + 2j = 6j
(4 + 6j + 2j2) = 0

Solving
4 + 6j + 2j2 = 0

Solving for variable 'j'.

Factor out the Greatest Common Factor (GCF), '2'.
2(2 + 3j + j2) = 0

Factor a trinomial.
2((2 + j)(1 + j)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(2 + j)' equal to zero and attempt to solve:

Simplifying
2 + j = 0

Solving
2 + j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + j = 0 + -2

Combine like terms: 2 + -2 = 0
0 + j = 0 + -2
j = 0 + -2

Combine like terms: 0 + -2 = -2
j = -2

Simplifying
j = -2
Subproblem 2
Set the factor '(1 + j)' equal to zero and attempt to solve:

Simplifying
1 + j = 0

Solving
1 + j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + j = 0 + -1

Combine like terms: 1 + -1 = 0
0 + j = 0 + -1
j = 0 + -1

Combine like terms: 0 + -1 = -1
j = -1

Simplifying
j = -1
Solution
j = {-2, -1}