(2j+3)/3=(3j-1)/6

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Solution for (2j+3)/3=(3j-1)/6 equation:



(2j+3)/3=(3j-1)/6
We move all terms to the left:
(2j+3)/3-((3j-1)/6)=0
We calculate fractions
2j/()+(-((3j-1)*3)/()=0
We calculate terms in parentheses: +(-((3j-1)*3)/(), so:
-((3j-1)*3)/(
We multiply all the terms by the denominator
-((3j-1)*3)
We calculate terms in parentheses: -((3j-1)*3), so:
(3j-1)*3
We multiply parentheses
9j-3
Back to the equation:
-(9j-3)
We get rid of parentheses
-9j+3
Back to the equation:
+(-9j+3)
We get rid of parentheses
2j/()-9j+3=0
We multiply all the terms by the denominator
2j-9j*()+3*()=0
We add all the numbers together, and all the variables
2j-9j*()=0

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