(2d-6)/(2d-4)*(4)/(d-4)*(d-2)/(3d-9)

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Solution for (2d-6)/(2d-4)*(4)/(d-4)*(d-2)/(3d-9) equation: 


D( d )

3*d-9 = 0

d-4 = 0

2*d-4 = 0

3*d-9 = 0

3*d-9 = 0

3*d-9 = 0 // + 9

3*d = 9 // : 3

d = 9/3

d = 3

d-4 = 0

d-4 = 0

d-4 = 0 // + 4

d = 4

2*d-4 = 0

2*d-4 = 0

2*d-4 = 0 // + 4

2*d = 4 // : 2

d = 4/2

d = 2

d in (-oo:2) U (2:3) U (3:4) U (4:+oo)

(((4*((2*d-6)/(2*d-4)))/(d-4))*(d-2))/(3*d-9) = 0

(4*(2*d-6)*(d-2))/((2*d-4)*(d-4)*(3*d-9)) = 0

( 2*d-6 )

2*d-6 = 0 // + 6

2*d = 6 // : 2

d = 6/2

d = 3

( 4 )

4 = 0

d belongs to the empty set

( d-2 )

d-2 = 0 // + 2

d = 2

d in { 3} 

d in { 2} 

d belongs to the empty set

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