(2d-5)/2=(5d+2)/9

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Solution for (2d-5)/2=(5d+2)/9 equation: 



(2d-5)/2=(5d+2)/9

We move all terms to the left:

(2d-5)/2-((5d+2)/9)=0

We calculate fractions


2d/()+(-((5d+2)*2)/()=0



We calculate terms in parentheses: +(-((5d+2)*2)/(), so:

-((5d+2)*2)/(

We multiply all the terms by the denominator


-((5d+2)*2)



We calculate terms in parentheses: -((5d+2)*2), so:

(5d+2)*2

We multiply parentheses

10d+4

Back to the equation:

-(10d+4)



We get rid of parentheses

-10d-4

Back to the equation:

+(-10d-4)



We get rid of parentheses

2d/()-10d-4=0

We multiply all the terms by the denominator


2d-10d*()-4*()=0

We add all the numbers together, and all the variables

2d-10d*()=0

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