(2cosx-1)(2cosx+1)=3

Solution for (2cosx-1)(2cosx+1)=3 equation:

Simplifying
(2cosx + -1)(2cosx + 1) = 3

Reorder the terms:
(-1 + 2cosx)(2cosx + 1) = 3

Reorder the terms:
(-1 + 2cosx)(1 + 2cosx) = 3

Multiply (-1 + 2cosx) * (1 + 2cosx)
(-1(1 + 2cosx) + 2cosx * (1 + 2cosx)) = 3
((1 * -1 + 2cosx * -1) + 2cosx * (1 + 2cosx)) = 3
((-1 + -2cosx) + 2cosx * (1 + 2cosx)) = 3
(-1 + -2cosx + (1 * 2cosx + 2cosx * 2cosx)) = 3
(-1 + -2cosx + (2cosx + 4c2o2s2x2)) = 3

Combine like terms: -2cosx + 2cosx = 0
(-1 + 0 + 4c2o2s2x2) = 3
(-1 + 4c2o2s2x2) = 3

Solving
-1 + 4c2o2s2x2 = 3

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 4c2o2s2x2 = 3 + 1

Combine like terms: -1 + 1 = 0
0 + 4c2o2s2x2 = 3 + 1
4c2o2s2x2 = 3 + 1

Combine like terms: 3 + 1 = 4
4c2o2s2x2 = 4

Divide each side by '4o2s2x2'.
c2 = o-2s-2x-2

Simplifying
c2 = o-2s-2x-2

Take the square root of each side:
c = {-1o-1s-1x-1, o-1s-1x-1}