(2c-3)+(5c+9)=41

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Solution for (2c-3)+(5c+9)=41 equation:


Simplifying
(2c + -3) + (5c + 9) = 41

Reorder the terms:
(-3 + 2c) + (5c + 9) = 41

Remove parenthesis around (-3 + 2c)
-3 + 2c + (5c + 9) = 41

Reorder the terms:
-3 + 2c + (9 + 5c) = 41

Remove parenthesis around (9 + 5c)
-3 + 2c + 9 + 5c = 41

Reorder the terms:
-3 + 9 + 2c + 5c = 41

Combine like terms: -3 + 9 = 6
6 + 2c + 5c = 41

Combine like terms: 2c + 5c = 7c
6 + 7c = 41

Solving
6 + 7c = 41

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 7c = 41 + -6

Combine like terms: 6 + -6 = 0
0 + 7c = 41 + -6
7c = 41 + -6

Combine like terms: 41 + -6 = 35
7c = 35

Divide each side by '7'.
c = 5

Simplifying
c = 5

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