(2c+4)(2c-4)=

Solution for (2c+4)(2c-4)= equation:

Simplifying
(2c + 4)(2c + -4) = 0

Reorder the terms:
(4 + 2c)(2c + -4) = 0

Reorder the terms:
(4 + 2c)(-4 + 2c) = 0

Multiply (4 + 2c) * (-4 + 2c)
(4(-4 + 2c) + 2c * (-4 + 2c)) = 0
((-4 * 4 + 2c * 4) + 2c * (-4 + 2c)) = 0
((-16 + 8c) + 2c * (-4 + 2c)) = 0
(-16 + 8c + (-4 * 2c + 2c * 2c)) = 0
(-16 + 8c + (-8c + 4c2)) = 0

Combine like terms: 8c + -8c = 0
(-16 + 0 + 4c2) = 0
(-16 + 4c2) = 0

Solving
-16 + 4c2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 4c2 = 0 + 16

Combine like terms: -16 + 16 = 0
0 + 4c2 = 0 + 16
4c2 = 0 + 16

Combine like terms: 0 + 16 = 16
4c2 = 16

Divide each side by '4'.
c2 = 4

Simplifying
c2 = 4

Take the square root of each side:
c = {-2, 2}