(2c+12)(12-2c)=

Solution for (2c+12)(12-2c)= equation:

Simplifying
(2c + 12)(12 + -2c) = 0

Reorder the terms:
(12 + 2c)(12 + -2c) = 0

Multiply (12 + 2c) * (12 + -2c)
(12(12 + -2c) + 2c * (12 + -2c)) = 0
((12 * 12 + -2c * 12) + 2c * (12 + -2c)) = 0
((144 + -24c) + 2c * (12 + -2c)) = 0
(144 + -24c + (12 * 2c + -2c * 2c)) = 0
(144 + -24c + (24c + -4c2)) = 0

Combine like terms: -24c + 24c = 0
(144 + 0 + -4c2) = 0
(144 + -4c2) = 0

Solving
144 + -4c2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-144' to each side of the equation.
144 + -144 + -4c2 = 0 + -144

Combine like terms: 144 + -144 = 0
0 + -4c2 = 0 + -144
-4c2 = 0 + -144

Combine like terms: 0 + -144 = -144
-4c2 = -144

Divide each side by '-4'.
c2 = 36

Simplifying
c2 = 36

Take the square root of each side:
c = {-6, 6}