(2c)/(11)=(c-3)/(4)

Solution for (2c)/(11)=(c-3)/(4) equation:

(2c)/(11)=(c-3)/(4)

We move all terms to the left:

(2c)/(11)-((c-3)/(4))=0

We calculate fractions


8c^2/()+(-((c-3)*11)/()=0


We calculate terms in parentheses: +(-((c-3)*11)/(), so:

-((c-3)*11)/(

We multiply all the terms by the denominator


-((c-3)*11)


We calculate terms in parentheses: -((c-3)*11), so:

(c-3)*11

We multiply parentheses

11c-33

Back to the equation:

-(11c-33)


We get rid of parentheses

-11c+33

Back to the equation:

+(-11c+33)


We get rid of parentheses

8c^2/()-11c+33=0

We multiply all the terms by the denominator


8c^2-11c*()+33*()=0

We add all the numbers together, and all the variables

8c^2-11c*()=0