(2b-4)(2b+3)+(2b+6)(b-5)=(3b+3)*(2b+6)

Solution for (2b-4)(2b+3)+(2b+6)(b-5)=(3b+3)*(2b+6) equation:

(2b-4)(2b+3)+(2b+6)(b-5)=(3b+3)(2b+6)

We move all terms to the left:

(2b-4)(2b+3)+(2b+6)(b-5)-((3b+3)(2b+6))=0

We multiply parentheses ..

(+4b^2+6b-8b-12)+(2b+6)(b-5)-((3b+3)(2b+6))=0


We calculate terms in parentheses: -((3b+3)(2b+6)), so:

(3b+3)(2b+6)

We multiply parentheses ..

(+6b^2+18b+6b+18)

We get rid of parentheses

6b^2+18b+6b+18

We add all the numbers together, and all the variables

6b^2+24b+18

Back to the equation:

-(6b^2+24b+18)


We get rid of parentheses

4b^2-6b^2+6b-8b+(2b+6)(b-5)-24b-12-18=0

We multiply parentheses ..

4b^2-6b^2+(+2b^2-10b+6b-30)+6b-8b-24b-12-18=0

We add all the numbers together, and all the variables

-2b^2+(+2b^2-10b+6b-30)-26b-30=0

We get rid of parentheses

-2b^2+2b^2-10b+6b-26b-30-30=0

We add all the numbers together, and all the variables

-30b-60=0

We move all terms containing b to the left, all other terms to the right

-30b=60

b=60/-30

b=-2