(2b-11)+55+(4b+6)=180

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Solution for (2b-11)+55+(4b+6)=180 equation: 



(2b-11)+55+(4b+6)=180

We move all terms to the left:

(2b-11)+55+(4b+6)-(180)=0

We add all the numbers together, and all the variables

(2b-11)+(4b+6)-125=0

We get rid of parentheses

2b+4b-11+6-125=0

We add all the numbers together, and all the variables

6b-130=0

We move all terms containing b to the left, all other terms to the right

6b=130

b=130/6

b=21+2/3

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